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cot7 0^@+4cos7 0^@...

`cot7 0^@+4cos7 0^@`

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The value of cot70^0+4cos70^0 is

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4 cos 36^(@) + cot 7 (1^(@))/(2)=

4cos36 ^ (@) + cos (7 (1) / (2)) ^ (0) =

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Prove that: \ cos7^0cos 14^0cos 28^0cos 56^0=(sin 68^0)/(16cos83^0)