10(a+2b+5c)^(2)

Expand : (iii) (a+ 2b- 5c )^2

Expand : (i) (a+b-c)^(2) " " (ii) (a-2b-5c)^(2) " " (iii) (3a-2b-5c)^(2) " " (iv) (2x+(1)/(x)+1)^(2) .

Expand : (i) (a+b-c)^(2) " " (ii) (a-2b-5c)^(2) " " (iii) (3a-2b-5c)^(2) " " (iv) (2x+(1)/(x)+1)^(2) .

Expand : (iv) (a - 2 b - 5c )^2

Expand (i) (a+2b+5c)^2 (ii) (2a+b+c)^2 (iii) (a-2b-3c)^2

If a,b,c are positive real numbers,then 3125a^(10)b^(5)c^(10)5 is equal to 5a^(2)bc^(2)( b) 25ab^(2)c5a^(3)bc^(3)(d)125a^(2)bc^(2)

(3a-2b)^(3)+(2b-5c)^(3)+(5c-3a)^(3)

If a+b=5 and 3a+2b=20, then (3a+b) will be: (a)10 (b) 15 (c) 20 (d) 25