" (ii) "t^(3)+7r^(2)+14t+8

Equation of displacement for any particle is s = 3t^(3) +7t^(2) +14t8m . Its acceleration at time t = 1 sec is

Motion of a particle is given by equation S = (3t^(3) + 7 t^(2) + 14 + t + 8) m, The value of acceleration of the particle at t = 1 sec, is:

Motion of a particle is given by equation S = (3t^(3) + 7 t^(2) + 14 + t + 8) m, The value of acceleration of the particle at t = 1 sec, is:

Motion of particle is given by equation s=(3t^(3)+7t^(2)+14t+8)m The value of acceleration of the particle at t = 1 s is

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

The displacement of particle with respect to time is s = 3^(t3) - 7t^(2) + 5t + 8 where s is in m and t is in s, then acceleration of particle at t = ls is

The displacment of a particle is represented by the following equation : s=3t^(3)+7t^(2)+4t+8 where s is in metre and t in second. The acceleration of the particle at t=1:-

Subtract : 3t ^(4) - 4t ^(3) + 2t ^(2) - 6t + 6 from - 4t ^(4) + 8t ^(3) - 4t ^(2) - 2t + 11

Select the correct answer from the given alternative. If for a G. P. (t _(6))/( t _(3))= ( 14 5 8)/( 54) then r = ?