Let ` f(x)={ -x^3+log2b, 0ltxlt1; 3x, xgeq1}`. Then minimum value of b-11 for which f(x) has least value at x=1 is

Let f(x)={{:(3x^2-2x+10, x lt 1),(-2,x gt 1):} The set of values of b for which f(x) has greatest value at x=1 is

"Let "f(x) ={underset(-2x + log_(2) (b^(2)-2), x gt1)(x^(3) -x^(2) +10 x-5 , x le 1). The set of values of b for which f(x) has greatest value at x= 1 is given by .

Let f (x) = {{:( x^(3) - x^(2) + 10 x- 5 , "," , x le 1), ( -2x + log _(2) (b^(2) - 2) , "," , x gt 1):} the set of values of b for which f(x) has greatest value at x = 1 is given by

Let f(x) = {(x^(3) - x^(2) + 10x - 5",", x le 1),(-2x + log_(2)(b^(2) - 2)",",x gt 1):} find the values of b for which f(x) has the greatest value at x = 1.

Let f(x)={x^3-x^2+10 x-5,xlt=1-2x+(log)_2(b^2-2),x >1 Find the values of b for which f(x) has the greatest value at x=1.

Let f(x)={x^3-x^2+10 x-5,xlt=1-2x+(log)_2(b^2-2),x >1 Find the values of b for which f(x) has the greatest value at x=1.

Let f(x)={(-x^(3)+log_(2)a,0<=x<1),(3x,1<=x<=3)} ,the complete set of real values of a for which f(x) has smallest value at x=1 is

Let f(x)={x^3-x^2+10 x-5,xlt=1, \ -2x+(log)_2(b^2-2),x >1 Find the values of b for which f(x) has the greatest value at x=1.