" 16) If "f(x)=|x-1|,x varepsilon R" ,then at "x=1^(***)" ,"1" point "

If f(x) =|x-1| ,x in R then at x =1

If 2f(x^(2))+3f((1)/(x^(2)))=x^(2)-1x varepsilon R_(0) then f(x^(2)) is

Let f(x)=x+f(x-1) where x varepsilon R. If F(0)=1 find f(100)

Let f(x)=minimum{|x|,1-|x|,(1)/(4)} for x varepsilon R then the value of int_(-1)^(1)f(x)dx is equal to

Solve (|x|-1)/(|x|-2)>=0;x varepsilon R;x=+-2

Prove that f (x) = |x-1|,x in R is not differnentiable at x=1

f(x)=max(sin x,cos x),x varepsilon R. Then number of critical points varepsilon(-2 pi,2 pi) is/are (i) 5( ii) 7( iii) 9 (iv) none of these

Let f(x) is defined on the interval [0,1] by f(x)={x,x varepsilon Q and (1-x),x!=Q}, where Q is the set of rational numbers.

Let f(x)=(1)/(1+|x|) ; x in R the range of f is

Prove that the function f given by f(x) = |x-1|, x in R, x=1 is not differentiable at x = 1.