4y=-24" and "(3x)/(2)-(5y)/(3)=-2

Solve for x and y:(2x+1)/(7)+(5y-3)/(3)=12(3x+2)/(2)-(4y+3)/(9)=13

Solve for x and y:3x^(2)-5y^(2)=7,3xy-4y^(2)=2

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18

the radical axis of the circles x^(2) + y^(2) + 3x + 4y - 5 = 0 " and " x^(2) + y^(2) - 5x + 5y - 6 = 0 is

the slope of the radical axis of the circles x^(2) + y^(2) + 3x + 4y - 5 = 0 " and " x^(2) + y^(2) - 5x + 5y - 6 = 0 is

The radical axis of circles x^(2) + y^(2) + 5x + 4y - 5 = 0 and x^(2) + y^(2) - 3x + 5y - 6 = 0 is

The y-axis and the lines (a^(5)-2a^(3))x+(a+2)y+3a=0 and (a^(5)-3a^(2))x+4y+a-2=0 are concurrent for

Find,whether or not the first polynomial is a factor of the second: x+1,2x^(2)+5x+4y-2,3y^(3)+5y^(2)+5y+24x^(2)-5,4x^(4)+7x^(2)+15

Factorise : (viii) (3x - 2y)^(2) - 5 (3x -2y) - 24