Let AP and BQ be two vertical poles at points A and B, respectively. If `A P = 16 m , B Q = 22 m a n d A B = 20 m`, then find the distance of a point R on AB from the point A such that `R P^2+R Q^2`is minimum.

Explanation

Let R be a point on AB such that AR=x metres, RB=(20-x) metres


`therefore RP^2 = AR^2+AP^2=x^2+16^2`

and `RQ^2=RB^2+BQ^2`


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