" (iv) "Lt(e^(x)-1)/(x)

underset(x to 0)"Lt" (e^(mx)-1)/(x)=

underset(x to 0)"Lt" (e^(sin x)-1)/(x)=

Show that Lt_(x to 0)(e^(x)-1)/(x)=1

Compute Lt_(x to 0)(e^(3x)-1)/(x) .

In the neighbourhood of x=0 it is known that 1+|x|lt(e^(x)-1)/(x)lt1-|x|"then find"lim_(xto0)(e^(x)-1)/(x).

In the neighbourhood of x=0 it is known that 1+|x|lt(e^(x)-1)/(x)lt1-|x|"then find"lim_(xto0)(e^(x)-1)/(x).

In the neighbourhood of x=0 it is known that 1+|x|lt(e^(x)-1)/(x)lt1-|x|"then find"lim_(xto0)(e^(x)-1)/(x).

In the neighbourhood of x=0 it is known that 1+|x|lt(e^(x)-1)/(x)lt1-|x|"then find"lim_(xto0)(e^(x)-1)/(x).

underset(x to 0)"Lt" (e^(tan x)-1)/(sin x)=

underset(x to 1)"Lt" (sin(e^(x-1)-1))/(log x)=