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The number of normal (s) to the parabola...

The number of normal (s) to the parabola `y^2=8x` through (2, 1) is (B) 2 (A) 1 (D) 3 (C) 0

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Equation of the normal of the parabola ` y^2 = 4ax` is given by,
` y = mx - 2am-am^3->(1)`
Now, in the given parabola, `y^2 = 8x`
`a = 2`
Putting value of `a` in (1),
`=>y = mx-4m-2m^3`
At point `(2,1)` this equation becomes,
`=>1= 2m-4m-2m^3`
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