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The graph of 1n (R/R0) versus 1n A (R = ...

The graph of `1n (R/R_0)` versus `1n A (R = radius` of a nucleus and `A =` its mass number) is

A

a straight line

B

a parabola

C

and ellipse

D

a circle

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The correct Answer is:
A
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The ratio of r_(n)//r_(0) (r_(n) = "radius of nucleus and "r_(0)"is radius of atom ")

A : Nuclear density is almost same for all nuclei . R: The radius (r ) of a nucleus depends only on the mass number (A) as r prop A^(1//3) .

If A is mass number of a nucleus of Radius R, then

Size of nucleus was obtained by the equation r=R_(0)A^(1//3) , Where r is the radius of nucleus of mass no A. and R_(0) is a constant whose valie is equal to 1.5xx10^(-15) metre. (Given : 1 amu = 1.66xx10^(-24)g ) What is the density of a nucleus of mass number A ?

Radius of a nucleus is given by the relation R = R_(0)A^(1//3) where R_(0) = 1.3 xx 10^(-15) m and A is mass number. For a nucleon inside a nucleus, de-Broglie wavelength is given by diameter of the nucleus. Average kinetic energy of a nucleon in the Te^(128) nucleus based on above information will be :

The radius of nucleus is r=r_(0)A^(1//3) , where A is mass number. The dimensions of r_(0) is

Radius (r_(n)) of electron in nth orbit versus atomic number (Z) graph is

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