Cut off potential for a metal in photoel...

Cut off potential for a metal in photoelectric effect for light of wavelength `lambda_(1), lambda_(2)` and `lambda_(3)` is found to be `V_(1),V_(2)` and `V_(3)` volts , If `V_(1),V_(2)` and `V_(3` are in Arithmetic progression then `lambda_(1),lambda_(2)` and `lambda_(3)` will be in

Arithmetic progression

Geometric progression

Harmonic progression

None of these

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Cut off potentials for a metal in photoelectric effect for light of wavelength lambda_(1), lambda_(2) and lambda_(3) is found to be V_(1), V_(2) and V_(3) volts if V_(1), V_(2) and V_(3) are in Arithmetic Progression and lambda_(1), lambda_(2) and lambda_(3) will be :

Let be the maximum kinetic energy of photoelectrons emitted by light of wavelength lambda_(1) and lambda_(2) correspondingto wavelength lambda_(2) . If lambda_(1) = 2lambda_(2) then:

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The stopping potential for a certain photocell is 1.2 V when light of wavelength lambda_(1)=400 nm is used. It is 0.6 V, when light of wavelength lambda_(2)=500 nm is used. What would be the stopping potential, when both lambda_(1) and lambda_(2) are incident simultaneously ?

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