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The activity of a radioactive substance ...

The activity of a radioactive substance is `R_(1)` at time `t_(1)` and `R_(2)` at time `t_(2)(gt t_(1))`. Its decay cosntant is `lambda`. Then .

A

`R_(1)t_(1)=R_(2)t_(2)`

B

`R_(1)=R_(1)e^(-(lambda^(t_(1)-t_(2))))`

C

`(R_(1)-R_(2))/(t_(2)-t_(1))`=constant

D

`R_(2)=R_(1)e^(lambda(t_(2)-t_(1))`

Text Solution

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The correct Answer is:
B
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