Two identical photocathode receive light of frequencies `f_(1)` and `f_(2)`. If the maximum velocities of the photoelectrons (of mass `m`) coming out are respectively `v_(1)` and `v_(2)` then:

Options

A. `v_(1)-v_(2)=[(2h)/(m)(f_(1)-f_(2))]^(1//2`
B. ` v_(1)^(2)-v_(2)^(2)=(2h)/(m)(f_(1)-f_(2))`
C. `v_(1)+v_(2)=[(2h)/(m)(f_(1)-f_(2))]^(1//2`
D. ` v_(1)^(2)+v_(2)^(2)=(2h)/(m)(f_(1)-f_(2))`

Answer

B