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7(y+3)-2(x+2)= 14, 4(y-2)+3(x-3)=2....

`7(y+3)-2(x+2)= 14, 4(y-2)+3(x-3)=2. `

Text Solution

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`7(y+3) - 2(x+2) = 14`
`=> 7y+21-2x-4 = 14`
`=>7y-2x = -3`
`=>2x-7y = 3->(1)`
`4(y-2)+3(x-3) = 2`
`=>4y-8+3x-9 = 2`
`=>3x+4y = 19->(2)`
Multiplying (1) by `4` and (2) by `7` and adding both,
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