(x^(a(b-c)))/(x^(b(a-c)))-:((x^(b))/(x^(a)))^(c)

Simplify: ((x^(a+b))/(x^(c)))^(a-b)((x^(b+c))/(x^(a)))^(b-c)((x^(c+a))/(x^(b)))^(c-a)(x^(l))/(x^(m))lm x(x^(m))/(x^(n))mnx(x6n)/(x^(l))ln

Prove that :((x^(a))/(x^(b)))^(a+b-c)((x^(b))/(x^(c)))^(b+c-a)((x^(c))/(x^(a)))^(c+a-b)=1

If x is a positive real number and the exponents are rational numbers,show that: ((x^(a))/(x^(b)))^(a+b-c)((x^(b))/(x^(c)))^(b+c-a)((x^(c))/(x^(a)))^(c+a-b)=1

((x^(a))/(x^(b)))^(a+b-c)*((x^(b))/(x^(c)))^(b+c-a)*((x^(c))/(x^(a)))^(c+a-b)= a.1 b.x^(abc) c.x^(ab+bc+ca) d.x^(a+b+c)

Simplify: ((x^(a))/(x^(-b)))^(a-b)xx((x^(b))/(x^(-c)))^(b-c)xx((x^(c))/(x^(-a)))^(c-a)

((x^(a))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a)=? a.0 b.x^(abc) c.x^(a+b+c)d.1=? a.0

Differentiate ((x^(a))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a) with respect to x.

Assuming that x is a positive real number and a,b,c are rational numbers,show that: ((x^(a))/(x^(b)))^(a+b)((x^(b))/(x^(c)))^(b+c)((x^(c))/(x^(a)))^(c+a)=1

Simplify: (i)\ ((x^(a+b))/(x^c))^(a-b)\ ((x^(b+c))/(x^a))^(b-c)\ ((x^(c+a))/(x^b))^(c-a) (ii)\ ((x^l)/(x^m))^(1/(lm))\ xx\ ((x^m)/(x^n))^(1/(mn))\ xx\ \ ((x^n)/(x^l))^(1/(ln))

Prove that: ((x^(a))/(x^(b)))^(c)x((x^(b))/(x^(c)))^(a)x((x^(c))/(x^(a)))^(b)=1