`int(sintheta+costheta)* d theta`

The value of int(1)/(sintheta+costheta)d theta is equal to ?

Prove that int_0^(pi/2)(costheta-sintheta)/(1+sintheta.costheta)d theta=0.

If (sintheta+costheta)/(sintheta-costheta)=3 and theta is an acute angle, then the value of (3sintheta+4costheta)/(8costheta-3sintheta) is

int(cos2theta)/((sintheta+costheta)^2)d theta is equal to

If int(sintheta-costheta)/((sintheta+costheta)sqrt(sinthetacostheta+sin^(2)thetacos^(2)theta))d theta = "cosec"^(_1)(f(theta))+C , then

int(costheta)/(7+sintheta-2cos^2theta)d theta is equal to

The value of int(1+sin2theta)/(sintheta-costheta)d""theta is equal to

The value of int(1+sin2theta)/(sintheta-costheta)d""theta is equal to

underset0 overset(pi//2)int (sintheta)/sqrt(1+costheta) d theta

int(cos2theta)/((sintheta+costheta)^(2))d""theta is equal to