Calculate the voltage needed to balance on all drop carrying 10 electrons when located between the plates of a capacitor which are 5 mm apart. Mass of oil drop is `3xx10^(-16) kg `(take `g = 10m//s^(2))`

Calculate the voltage required to balanced an oil drop carrying 10 electrons, when located between plates of a capacitor, which are 5mm apart. Given mass of drop = 3xx10^(-16) kg , charge on electron = 1.6xx10^(-19)C and g = 9.8 m//s^(2) .

An oil drop with charge 1.6xx10^(-18)C is balanced in air between two metallic plates 10 mm apart. Calculate the voltage required between the plates if mass of the drop is 2.4xx10^(-14)kg .

A charged oil drop of mass 2.5xx10^(-7) kg is in space between the two plates, each of area 2xx10^(-2) m^(2) of a parallel plate capacitor. When the upper plate has a charge of 5 xx10^(-7) C and the lower plate has an equal negative charge, then the oil remains stationary. the charge of the oil drop is (take, g=10 m//s^(2) )

Calculate the ratio between the wavelength of an electron and a proton, if the proton is moving at half the velocity of the electron (mass of the proton =1.67xx10^(-27)kg , mass of the electron =9.11xx10^(-2)m .

Two plane parallel conducting plates 1.5xx10^(-2)m apart are held horizontal one above the other in air. The upper plate is maintained at a positive potential of 1.5kV while the other plate is earthed. Calculate the number of electrons which must be attached to a small oil drop of mass 4.8xx10^(-15)kg between the plates of move the drop with constant speed. Neglect the density and viscosity of air.

Two plane parallel conducting plates 1.5xx10^(-2)m apart are help horizontally one aove the other in air. The upper plate is maintained at positive potential of 1.5 kV while the other plate is earthed. Calculate the number of electorns which must be attached to a small oil drop of mass 4.9xx10^(-15)"kg" between the plates to maintain it at rest. If the potential of upper plate is suddenly changed to -1.5 kV, what is the initial acceleration of the charged drop ? Also obtain the terminal velocity of the drop if its radius is 5xx10^(-6)m and coefficient of viscosity of air is 1.8xx10^(-5)N-s//m^(2) . Assuming that the density of air is negligible in comparison with that of oil.

The plate area of a parallel-plate capacitors is 10cm^(2) and its capacitance is 2pF . The separation between the plates of the capacitors is close to (in mm). (permittivity of vacuum, epsi_(0)=(80)/(9)xx10^(-12)m^(-3)kg^(-1)s^(4)A^(2),1pF=10^(-12)F )