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Two protons in a U^(238) nucleus are 6.0...

Two protons in a `U^(238)` nucleus are `6.0xx10^(-15)m` apart. What is their mutual electric potential energy?

Text Solution

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The correct Answer is:
`2.4xx10^(5)eV`
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The classical method of a hydrogen atom in its normal, unexcited configuration has an electron that revolves around a proton at a distance of 5.3 xx 10^(11)m . (a) What is the electric potential due to the proton at the position of electron ? (b) Determine the electrostatic potential energy between the two particles.

The radius of a nucleus ofa mass number A is given by R=R_(0)A^(1//3) , where R_(0)=1.3xx10^(-15)m . Calculate the electrostatic potential energy between two equal nuclei produced in the fission of ._(92)^(238)U at the moment of their fission

Knowledge Check

  • The nucleus of helium atom contains two protons that are separated by distance 3.0xx10^(-15)m . The magnitude of the electrostatic force that each proton exerts on the other is

    A
    20.6 N
    B
    25.6 N
    C
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    D
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  • In an hydrogen atom, the electron revolves around the nucles in an orbit of radius 0.53 xx 10^(-10) m . Then the electrical potential produced by the nucleus at the position of the electron is

    A
    `-13.6 V`
    B
    `-27.2 V`
    C
    `27.2 V`
    D
    `13.6 V`

  • A beam of alpha paricles is incident on a target of lead. A particular alpha paticles comes in 'head- on' to a particular lead nucleus and stops 6.50 xx 10^(-14) m away from the center of the nucleus. (This point is well outside the nucleus.) Assume that the lead nucleus, which has 82 protons, remains at rest. The mass of alpha particle is 6.64 xx 10^(-27)kg Calculate the electrostatic potential energy at the instant when the alpha particle stops?

    A
    `36.3MeV`
    B
    `45.0MeV`
    C
    `3.63MeV`
    D
    `40.0MeV`

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    The radius of nucleus of sliver (atomic number = 47 ) is 3.4 xx 10^(-14)m . The electric potential on the surface of uncleus is (e = 1.6 xx 10^(-19) C)

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