" 27."(a+b)^(3)-a-b

Factorise : (i) 9a^(3)-27b^(3) " " (ii) a^(3)-343 " " (iii) a^(3)-(27)/(a^(3)) " " (iv) 1+8a^(3) " " (v) (a+b)^(3)-(a-b)^(3) .

If a+b = 7/3 and a^(2) + b^(2) = 31/9 , find 27(a^(3) + b^(3))

If a^(1/3)+b^(1/3)+c^(1/3)=0 show that (a+b+c)^(3)=27 abc

If a^(1//3)+b^(1//3)+c^(1//3)=0 , then show that (a+b+c)^(3)=27 abc .

Divide : 18a^(3)b^(2) - 27 a^(2)b^(3) +9ab^(2) by 3ab

27a^3b^3-45a^4b^2

Factorise: 18a ^(3) b^(3) - 27a ^(2) b^(3) + 36 a ^(3)b ^(2)