In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of `2.0xx10^(16)Hz` and amplitude `48Vm^(-1)`
What is the amplitude of the oscillating magnetic field?

In a plane electromagnetic wave, the electric field oscillates sinnusoidally at a frequency of 2xx10^(10)Hz and amplitude 48 V//m . The amplitude of oscillating magnetic field will be

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.5xx10^10Hz and amplitued 480V//m . The amplitude of oscillating magnetic field will be

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0xx10^10 Hz and amplitude 48Vm^(-1) . The total energy density of the electromagnetic field of the wave is :

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2xx10^(10)Hz and amplitude 48V//m . The wavelength of the wave will be-

In a place e.m wave, the electric field oscillates sinusoidally at a frequency of 2.5xx10^(10)Hz and amplitude 480 V//m .The amplitude of oscillating magnetic field will be,

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0xx10^10 H_z and amplitude 48V_m^-1 (a) What is the wavelength o f the wave? (b) What is the amplitude of the oscillating magnetic field. (c) Show that the average energy density of the field E equals the average energy density of the field B.[c=3xx10^8 ms^-1] .

In a plane electromagnetic wave the electric field osciallates sinusoidally at a frequency of 2.0 xx 10^(10) and amplitude 48 m^(-1) (a) What is the wavelength of the wave (b) What is the amplitude of the oscillating magnetic field ? (c ) show that the average energy density of the vecE field equals to the average energy density of the vecB field . [ c= 3.0 xx 10^8 m s^(-1) ]