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The distance between the two plates of a cathode-ray oscilloscope is 1 cm and the potential difference between them is 1200 V. If an electron of energy 2000 eV enters at right angles to the field, what will be its deflection if the plate be 1.5 cm long.

Answer

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The distance between the two plates of a parallel plate capacitor is 1 cm and potentail differnece them is 1200 volts . If an electron of energy 200 eV enters at right angles to the field, what will be its deflection if the plates are 1.5 cm long ?

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Knowledge Check

  • If the electric field between the plates of a cathode ray oscilloscope be 1.2xx10^(4)N//C ,the deflection that an electron will experience if it enters at right angels to the field with kinetic energy 200eV is (the defelction assembly) is 1.5cm long

    A
    `0.34cm`
    B
    `3.4cm`
    C
    `0.034mm`
    D
    `0.34mm`

  • An electron enters between two horizontal plates separated by 2 mm and having a potential difference of 1000V . The force on electron is

    A
    `8 xx 10^(-12) N`
    B
    `8 xx 10^(-14) N`
    C
    `8 xx 10^(-9) N`
    D
    `8 xx 10^(14) N`

  • In the Millikan's experiment, the distance between two horizontal plates is 2.5 cm and the potential difference applied is 250 V .The electric field between the plates will be

    A
    900 V/m
    B
    10000 V/m
    C
    625 V/m
    D
    6250 V/m

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    The answer to each of the following questions is a single-digit integer ranging from 0 to 9. Darken the correct digit. A uniform electric field exists in between the plates of a capacitor and potential difference between the plates is found to be V_(1) . Now a dielectric slab of dielectric constant 2 is inserted in between the paltes. Thickness of the salb is half of the separation between the plates. The potential difference between the plates is V_(2) now. Calculate 3V_(1)//V_(2) .

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