A light source, emitting there wavelengths 500nm, 600nm and 700 nm, has a total power of `10^(-3) W` and a beam diameter `2xx10^(-3)m`. The density is distributed equally amongst the three wavelength. The beam shines normally on a metallic surface of area on `10^(-4) m^(2)` and having a work function of `1.9` eV. Assuming that each photon liberates an electron, calculate the charge emitted per unit area in one second.

A beam of light has three wavelengths 4000 Å, 5000 Å, 6000Å with a total intensity 3 xx 10^(-3) W//m^(2) equally distributed amongst the three wavelenth. The beam falls normally on an area 2 cm^(2) of clean metallic surface of work function 2.4 eV . Calculate photo current. (Assume each energetically suitable photon emits one electron)

A beam of light has three wavelengths 4144 Å , and 6216 Å with a total instensity of 3.6 xx 10^(-3) Wm^(-2) equally distributed amongst the three wavelengths. The beam falls normally on an area 1.0 cm^2 of a clean metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection number of photoelectrons liberated in two seconds.

A beam of light has two wavelengths 4,972Å and 6,216Å with a total intensity of 3.6xx10^(-3) W m^(-2) equally distributed among the two wavelengths . The beam falls normally on an area of 1 cm^2 of clean metallic surface of work function 2.3 eV . Assume that there is no loss of light by reflection and that each capable photon ejects one electron. The number of photoelectrons liberated in 2 s is approximately

A beam of light has three lambda, 4144 "Å", 4972 "Å" "and"6216 "Å" with a total intensity of 3.6 xx10^(-3) Wm^(-2) equally distributed amongst the three lambda. The beam falls normally on an area 1.0 cm^(2) of a cleam metallic surface of work function 2.3 eV. Assume that there is no loss of light by reflection etc. Calculate the no. of photoelectrons emitted in 2 sec, in scientific notation, x xx 10^(y) find the value of y.

A beam of light consists of four wavelength 4000Å , 4800 A, 6000 A and 7000 Å , each of intensity 1.5xx10^(-3)Wm^(-2) . The beam falls normally on an area 10^(-4)m^(2) of a clean metalic surface of work function 1.9 eV . Assuming no loss of light energy (i.e. each capable photon emits one electron) calculate the number of photoelectrons liberated per second.

A monochromatic source emitting light of wavelength, 600nm, has a power output of 66W. Caculate the number of photons emitted by this source in 2minuts. Use h=6.6xx10(-34)Js .

Light of wavelength 5000 Å and intensity of 3.96 xx 10^(-3) watt//cm^(2) is incident on the surface of photo metal . If 1% of the incident photons only emit photo electrons , then the number of electrons emitted per unit area per second from the surface will be

If Photon having wavelength 6.2nm was allowed to strike a metal plate having work function 50eV then calculate wavelength associated with emitted electron :