Interference fringes were produced by Young's double slit method, the wavelength of light used being 6000Å. The separation between the two slits is 2 mm.The distance between the slits and screen is 10 cm. When a transparent plate of thickness 0.5 mm is placed over one of the slits. the fringe pattern is displaced by 5 min. Find the refractive index of the material of the plate.

In Young's double slit experiment, the slits are 3 mm apart. The wavelength of light used is 5000 Å and the distance between the slits and the screen is 90 cm. The fringe width in mm is

In YDSE, separation between slits is 0.15 mm, distance between slits and screen is 1.5 m and wavelength of light is 589 nm, then fringe width is

A two slit Young's interference experiment it done with monochromatic light of wavelength 6000 A . The slits are 2 mm apart. The fringes are observed on a screen placed 10 cm away from the slits. Now a transparent plate of thickness 0.5 mm is placed in front of one of the slits and it if found that the interference pattern shifts by 5 mm . The refractive index of the transparent plate is :

A double slit experiment is done with monochromatic light of wavelength 6000 Å . Slits are 2 mm apart and fringes are observed on a screen placed 10 cm away from the slits. If a transparent plate of thickness 0.5 mm is placed in front of one of the slit, interference pattern shifts by 5 mm. Then refractive index of transparent plate should be :

In Young's double slit experiement when wavelength used is 6000Å and the screen is 40cm from the slits, the fringes are 0.012cm wide. What is the distance between the slits?

Interference fringes were produced in Young's double slit experiment using light of wavelength 5000 Ã…. When a film of material 2.5xx 10^(-3) cm thick was placed over one of the slits, the fringe pattern shifted by a distance equal to 20 fringe widths. The refractive index of the material of the film is