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In Lloyd's single mirror interference ex...

In Lloyd's single mirror interference experiment, the source slit is at a distance of 2 mm from the plane mirror . The screen is kept at a distance of 1.5m from the source . If light of wavelength 5890 `Å` is used, calculate the fringe width.

Text Solution

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The correct Answer is:
`0.221` mm
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In Lloyd's mirror interference experiment the source slit is at a distance of 2 mm from a plane mirror . The interference fringes , observed on a screen at a distance of 1.5 m from the slit , have a separation of 0.221 mm . Calculate the wavelength of light used .

In Lloyd's interference experiment, 10 fringes occupy a space of 1.5 mm. The distance between the source and the screen is 1.25 m. If light of wavelength 6000 Å is used, find the distance of the source from the plane minor.

Knowledge Check

  • In the Young's double slit experiment, the spacing between two slits is 0.1mm . If the screen is kept at a distance of 1.0m from the slits and the wavelength of ligth is 5000Å , then the fringe width is

    A
    (a) `1.0cm`
    B
    (b) `1.5cm`
    C
    (c) `0.5cm`
    D
    (d) `2.0cm`

  • In Young's double-slit experiment, spacing between the two slits is 0.1 mm. If the screen is kept at a distance of 1.0 m from the slits and the wavelength of light is 5000 Å, then the fringe width is

    A
    `1.0cm`
    B
    `1.5 cm`
    C
    `0.5 cm `
    D
    `2.0cm`

  • Two coherent light sources S_1 and S_2 (lambda=6000Å) are 1mm apart from each other. The screen is placed at a distance of 25cm from the sources. The width of the fringes on the screen should be

    A
    (a) `0.015cm`
    B
    (b) `0.025cm`
    C
    (c) `0.010cm`
    D
    (d) `0.030cm`

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