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In a head-on collision between and alpha...

In a head-on collision between and `alpha`-particle and a gold nucleus, the distance of closest approach is 4.13 fermi. Calculate the energy of the particle. (1 fermi `= 10^(-15) m`)

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The correct Answer is:
5.51 MeV
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SL ARORA-ATOMS, NUCLEI AND MOLECULES-Problems For Self Practice
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