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An alpha particle of K.E. 10^(-12)J exhi...

An `alpha` particle of `K.E. 10^(-12)J` exhibits back scattering from a gold nucleus Z=79. What can be the maximum possible radius of the gold nucleus?

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The correct Answer is:
`3.64 xx 10^(-14)m`
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An alpha particle of K.E. 10^(-12)J exibits back scattering form a gold nucleus Z=79. What can be the maximum possible radius of the gold nucleus?

An alpha -particle of velocity 2.3xx10^7 m/s exhibits back scattering by a gold foil (Z=79).Predict the maximum possible radius of the gold nucleus approximately Charge of mass ratio for alpha -particle is 4.8xx10^7 C/kg.

An alpha paritcle carrying an electric charge 3.2 xx 10^(-19)C is at a distance of 13.8 xx 10^(15)m from a gold nucleus (atomic number=79). Calculate the fore exertedby the gold nucleus on the alpha particle.

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A beam of alpha -particle of velocity 2.1xx10^(7)m//s is scattered by a gold ofil (Z=79). Find the distance of closest approach of alpha - particle to the gold nucleus. for alpha -particle, 2e//m=4.8xx10^(7)kg^(-1) .

A 4MeV alpha particle is scattered by 20^@ , when it approaches a gold nucleus. Calculate the impact parameter if Z for gold is 79.

A n alpha -particle of velocity 1.6xx10^(7) m s^(-1) approaches a gold nucleii (Z=79) . Calculate the distance of closest approach. Mas of an alpha -particle =6.6xx10^(-27) kg .

In Rutherford experiment, a 5.3 MeV alpha -particle moves towards the gold nucleus (Z=79). How close does the alpha -particle to get the centre of the nucleus, before it comes momentarily to rest and reverses its motion? ( epsi_(0)=8.8xx10^(-12)F//m )

Large angle scattering of alpha- particle led Rutherford to the discovery of atomic nucleus. It is the tiny central core of every atom in which entire positive charge of the atom is concentrated. The distance of closet approach of alpha particle from the nucleus is r_(theta)=((Ze)(2e))/(4pi epsilon_(theta)((1)/(2)mv^(2))) This distance r_(theta) gave him the order of size of nucleus. Read the above passage and answer the followign question: (i) What is the distance of closet approach of an alpha particle of energy 7.7 MeV from gold nucleus (z=79)? (ii) What is the implication of this relation in day to day life?

SL ARORA-ATOMS, NUCLEI AND MOLECULES-Problems For Self Practice
  1. In a head-on collision between and alpha-particle and a gold nucleus, ...

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  2. An alpha particle of K.E. 10^(-12)J exhibits back scattering from a go...

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  3. A protom of energy 1 MeV is incident head-on on a gold nucleus (Z = 79...

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  4. In a head-on collision between an alpha-particle and a gold nucleus, t...

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  5. An alpha-particle of kinetic energy 7.68 MeV is projected towards the ...

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  6. An alpha particle of energy 4MeV is scattered through an angle of 180^...

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  7. What is the distance of closest approach to the nucleus for an alpha-p...

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  8. What is the impact parameter at which the scattering angle is 10^(@) f...

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  9. A 10kg satellite circles earth once every 2hr in an orbit having a rad...

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  10. At what speed must an electron revolve around the nucleus of hydrogen ...

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  11. The innermost orbit of the hydrogen atom has a diameter of 1.06Å what ...

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  12. Calculate the energy of the hydrogen atom in the states n = 4 and n = ...

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  13. Calculate (i) the radius of the second orbit of hydrogen atom, and (ii...

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  14. Calculate the frequency of the photon, which can excite the electron ...

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  15. The ground state energy of hydrogen atom is -13.6eV. If an electron ma...

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  16. Show that the ionisation potential of hydrogen atom is 13.6 volt.

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  17. Calculate the ionisation potential of a single ionised He-atom.

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  18. Calculate the minimum energy that must be given to a hydrogen atom so ...

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  19. What energy in eV will be required to excite the ground state electron...

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  20. By giving energy to a hydrogen atom in energy state n=1. If the potent...

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