A dry cell of emf 1.5V and internal resistance 0.10 `Omega` is connected across a resistor in series with a very low resistance ammeter: When the circuit is switched on, the ammter reading settles to a steady value of 2.0A. What is the steady
(a) rate of chemical energy consumption of the cell,
(b) rate of energy dissipation inside the cell,
(c) rate of energy dissipation inside the resistor,
(d) power output of the source?

A dry cell of emf 1.5 V and internal resistance 0.10 Omega is connected across a resistor in series with a very low resistance ammeter. When the circuit is switched on , the ammeter reading settles to a steady value of 2.0 A . (i) What is the steady rate of chemical energy consumption of the cell ? What is the steady rate of energy dissipation inside the cell ? (ii) What is the steady rate of energy dissipation inside the cell ? (ii) What is the steady rate of energy dissipation inside the resistor ? (iv) What is the steady power out put of the source?

A dry cell of emf 1.6V and internal resistance 0.10 ohm is connected to a resistor of resistance R ohm. If the current drawn from the cell is 2A.

A dry cell of emf 1.6V and internal resistance 0.10 ohm is connected to a resistor of resistance R ohm. If the current drawn from the cell is 2A.

Six cells each of e.m.f. 2 V and internal resistance 0.1Omega are connected to three resistances as shown in figure. The reading of a low resistance ammeter A in the circuit is,

A battery of emf 12V and internal resistance 2 Omega is connected two a 4 Omega resistor. Show that the a voltmeter when placed across cell and across the resistor in turn given the same reading

A dry cell of emf 1.6V and internal resistance of 0.10 Omega is connected to a resistor of resistance R omega . If the current drawn the cell is 2A , then (i) What is the voltage drop across R ? (ii) What is the rate of energy dissipation in the resistor ?

A cell of e.m.f. 2V and internal resistance 0.5Omega is connected across a resistor R. The current that flows is same as that, when a cell of e.m.f. 1.5V and internal resistance 0.3Omega is connected across the same resistor. Then

A battery of emf 2 V and internal resistance r is connected in series with a resistor of 10Omega through an ammeter of resistance 2Omega . The ammeter reads 50 mA. Draw the circuit diagram and calculate the value of r.