Figure `6.12` shows a potentiometer circular for comparison of two resistances. The balance point with a standard resistor `R = 10.0 Omeag ` is found to be `58.3 cm`, while that with the unknows resistance `X` is `68.5 cm`. Determine the value of `X`. What would you do if you fail to find a balance point with the given cell `E`?

Figure shows a potentiometer circuit for comparision of two resistances. The balance point with a standard resistor R=10.0Omega is found to be 58.3 cm, while that with the unknown resistance X is 68.5 cm. the value of X is

In the potentimeter circuit shown in figure, the balance point with R = 10 Omega when switch S_(1) is closed and S_(2) is open is 50 cm, while that when S_(2) is closed and S_(1) is open is 60 cm. What is the value of x? What will you do if you fail to find a balance point with the given cell E'?

A potentiometer wire of length 1.0 m has a resistance of 10 Omega . It is connected to a 6 V battery in seried with a resistance of 5 Omega . Determine the emf of the primary cell which gives a balance point at 40 cm.

A potentiometer wire of length 1 m has a resistance of 100Omega . It is connected to a 6V battery in series with a resistance of 5Omega . Determine the emf of the primary cell which gives a balance point at 40cm.

Figure 6.13 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm . Whan a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm , length of the potentiometer. Dentermine the internal resistance of the cell.

A potentiometer wire of length 1.0 m has a resistance of 15 ohm. It is connected to a 5 V source in series with a resistance of 5 Omega . Determine the emf of the primary cell which has a balance point at 60 cm.