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It is intended to measure a maximum curr...

It is intended to measure a maximum current of 25 A with an ammeter of range 2.5 A and resistance `0.9Omega`. How will you do it? What will be the combined resistance?

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The correct Answer is:
`0.1Omega` in parallel, `0.09Omega`
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SL ARORA-ELECTRICAL INSTRUMENTS-Problem for self practice
  1. In a galvanometer there is a deflection of one divisions per mA. The i...

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  2. A galvanometer of resistanece 40Omega gives a deflection of 5 division...

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  3. It is intended to measure a maximum current of 25 A with an ammeter of...

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  4. A galvanometer has a resistance of 30Omega and a current of 2 mA is ne...

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  5. A galvanometer has a resistance of 100Omega. A difference of potential...

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  6. When a galvanometer having 20 divisions scale and 50Omega resistance i...

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  7. A galvanometer has a sensitivity of 60 division/ampere. When a shunt i...

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  8. A galvanometer of resistance 3663Omega gives full scale deflection for...

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  9. A shunt of 6Omega is connected across a galvanometer of resistance 294...

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  10. A galvanometer is shunted by 1/n th of its resistance. Find the fracti...

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  11. If a galvanometer is connected in series with a high resistance so tha...

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  12. A galvanometer has current sensitivity of 5 divisions/mA and a voltage...

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  13. A 250muA meter has 50 divisions and it needs 250 mV for full scale def...

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  14. It is required to pass only one-tenth of the main current through a ga...

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  15. With a potentiometer, null points were obtained at 140 cm and 180 cm w...

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  16. In a method for comparing emfs by a potentiometer a balance point is f...

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  17. In a potentiometer with a cell of unknown emf the balance point was ob...

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  18. A potentiometer having a wire 10 m long stretched on it, is connected ...

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  19. With a certain cell, the balance point is obtained at 60 cm from the z...

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  20. With a cell of emf 1.5 V, the balance point is obtained at a distance ...

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