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If a galvanometer is connected in series...

If a galvanometer is connected in series with a high resistance so that potential drop across the galvanometer is 1/n th of the total applied voltage, then show that the combined resistance of the galvanometer and the series resistor is n times the resistance of the galvanometer i.e.,

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The correct Answer is:
`R_(V)=nR_(g)`.
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SL ARORA-ELECTRICAL INSTRUMENTS-Problem for self practice
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