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Four resistances of 15Omega,12Omega,4Ome...

Four resistances of `15Omega,12Omega,4Omega and 10Omega` respectively are connected in cyclic order to form a wheatstone bridge. Is the network balanced? If not, calculate the resistance to be connected in parallel with the resistance of `10Omega` to balance the network

Text Solution

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The correct Answer is:
bridge is not balanced, `10Omega`
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Knowledge Check

  • Four resistances of 3Omega, 3Omega, 3Omega and 4Omega respectively are used to form a Wheatstone bridge. The 4Omega resistance is short circuited with a resistance R in order to get bridge balanced. The value of R will be

    A
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  • Four resistence of 10 Omega, 60Omega,100Omega and 200Omega , respectively taken in order are used to form a Wheatstone's bridge . A 15 V battery is connected to the ends of a 200Omega resistance, the current through it will be

    A
    `7.5xx10^(-5)A`
    B
    `7.5xx10^(-4)A`
    C
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  • Four resistances 3Omega, 6Omega, 4Omega , and 12Omega are connected so as to form Wheatstone's network. Shunt needed across 12Omega resistor to balance the bridge is

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