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" (i) "(1)/(4),-1

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The sum of the first 35 terms of the series (1)/(2) + (1)/(3) -(1)/(4) -(1)/(2) -(1)/(3) +(1)/(4) +(1)/(2) + (1)/(3) -(1)/(4)

(1)/(4)" " (1)/(2) " "(3)/(4)" "1" "1(1)/(4)" "1(1)/(2)" "1(3)/(4) ?

[[ Simplify: [3(1)/(4)-:{1(1)/(4)-(1)/(2)(2(1)/(2)-(1)/(4)-(1)/(6))}]

4(4)/(5)-:{2(1)/(5)-(1)/(2)(1(1)/(4)-(1)/(4)-(1)/(5))}

3log 2 +(1)/(4) -(1)/(2)((1)/(4))^(2)+(1)/(3)((1)/(4))^(3)-….. =

3log 2 +(1)/(4) -(1)/(2)((1)/(4))^(2)+(1)/(3)((1)/(4))^(3)-….. =

int_(0)^(1)1/((x^(2)+16)(x^(2)+25))dx is equal to a) 1/(5)[1/(4)"tan"^(-1)(1/(4))-1/(5)"tan"^(-1)(1/(5))] b) 1/(9)[1/(4)"tan"^(-1)(1/(4))-1/(5)"tan"^(-1)(1/(5))] c) 1/(4)[1/(4)"tan"^(-1)(1/(4))-1/(5)"tan"^(-1)(1/(5))] d) 1/(9)[1/(5)"tan"^(-1)(1/(4))-1/(4)"tan"^(-1)(1/(5))]