[7x-2y=1],[3x+4y-15]

Classify the following pairs of lines as coincident, parallel, perpendicular or intersecting : (i) 6x+14y-16=0 , 12x+28y-32=0 (ii) 3x-4y=8 , 3x+4y=11 (iii) 5x-2y=7 , 2y-5x=-7 (iv) 4x+7y=19 , 7x-4y=-2 (v) x-2y=7 , 4y-2x=13

If [[x-1,2y],[x+y,4]]=[[3x-7,y^2-3],[6,4]] then [[x,y]]=

3x+2y=14; x+4y=7

If the lines 7x+2y-8=0, 2x+y-1=0, 3x+4y+6=0 are concurrent, then the point of concurrence is

The equation of a line which is parallel to the line common to the pair of lines given by 6x^2-x y-12 y^2=0 and 15 x^2+14 x y-8y^2=0 and at a distance of 7 units from it is (a) 3x-4y=-35 (b) 5x-2y=7 (c) 3x+4y=35 (d) 2x-3y=7

The equation of a line which is parallel to the line common to the pair of lines given by 6x^2-x y-12 y^2=0 and 15 x^2+14 x y-8y^2=0 and at a distance of 7 units from it is 3x-4y=-35 5x-2y=7 3x+4y=35 2x-3y=7

The equation of a line which is parallel to the line common to the pair of lines given by 6x^2-x y-12 y^2=0 and 15 x^2+14 x y-8y^2=0 and at a distance of 7 units from it is 3x-4y=-35 5x-2y=7 3x+4y=35 2x-3y=7

The number of solutions of the system of equations: 2x+y-z=7x-3y+2z=1, is x+4y-3z=53(b)2 (c) 1 (d) 0

The perpendicular distance of the straight line 7x+24y=15 from the point of intersection of the lines 3x+2y+4=0, 2x+5y-1=0 is

Find the perpendicular distance between the point of intersection of 3x+2y+4=0, 2x+5y-1=0 and the line 7x+24y=15 .