Give a condition that three vectors ` vec a , vec b` and ` vec c` from the three sides of a triangle. What are the other possibilities?

For any three vectors vec a;vec b;vec c find [vec a+vec b;vec b+vec c;vec c+vec a]

If vec a,vec b,vec c represent the sides of a triangle taken in order,then write the value of vec a+vec b+vec *

If three unit vectors vec a,vec b, and vec c satisfy vec a+vec b+vec c=0, then find the angle between vec a and vec b

For any three vectors vec a, vec b, vec c, (vec a-vec b) * (vec b-vec c) xx (vec c-vec a) is equal to

If vec(A), vec(B) and vec(C ) are three vectors, then the wrong relation is :

Area of a triangle with adjacent sides determined by vectors vec a and vec b is 20. Then the area of the triangle with adjacent sides determined by vectors (2vec a+3vec b) and (vec a-vec b) is

The position vectors of the vertices A ,Ba n dC of a triangle are three unit vectors vec a , vec b ,a n d vec c , respectively. A vector vec d is such that vecd dot vec a= vecd dot vec b= vec d dot vec ca n d vec d=lambda( vec b+ vec c)dot Then triangle A B C is a. acute angled b. obtuse angled c. right angled d. none of these

Let vec a, vec b, vec c be three vectors from vec a xx (vec b xxvec c) = (vec a xxvec b) xxvec c, if

If vec a,vec b,vec c are three vectors such that vec a=vec b+vec c and the angle between vec b and vec c is (pi)/(2), then

Prove that,for any three vectors vec a,vec b,vec c[vec a+vec b,vec b+vec c,vec c+vec a]=2[vec a,vec b,vec c]