The dissolution of `Al(OH)_(3)` by a solution of `NaOH` results in the formation of

Options

A. `[Al(H_(2)O)_(4)(OH)_(2)]^(+)`
B. `[Al(H_(2)O)_(3)(OH)_(3)]`
C. `[Al(H_(2)O)_(2)(OH)_(4)]^(-)`
D. `[Al(H_(2)O)_(6)(OH)_(3)]`

Answer

C

Explanation

`Al(OH)_(3)` dissolves in NaOH solution to give `Al(OH)_(4)^(-)` ion which is supposed to have the octahedraol complex species `[Al(OH)_(4)(H_(2)O)_(2)]^(-)` in aqueous solution.
`Al(OH)_(3)+NaOH(aq) to [Al(OH)_(4)(H_(2)O)_(3)]^(-) (aq)+Na^(+)(aq)`.