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(i) P+C("carbon")+Cl(2) to Q+CO uaarr ...

(i) `P+C("carbon")+Cl_(2) to Q+CO uaarr`
(ii) `Q+H_(2)O to R+HCl`
(iii) `BN+H_(2)O to R+NH_(3) uarr`
(iv) `Q+LiAlH_(4) to S+LiCl+AlCl_(3)`
(v) `S+H_(2) to R+H_(2) uarr`
(vi) `S+NaH to T`
(P,Q,R,S annd T do not represent their chemical symbols)
Q. Compound S is:
(I) an odd `e^(-)` compound
(II) `(2c-3e^(-))` compound
(III) a electron deficient compound
(IV) a `sp^(2)` hybridized compound
Choose the correct code:

A

III

B

I,III

C

II,III,IV

D

I,II,IV

Text Solution

Verified by Experts

The correct Answer is:
A

(i) `underset((P))(B_(2)O_(3))+3C+3Cl_(2) to underset((Q))(2BCl_(3))+3CO uarr`
(ii) `underset((Q))(BC l_(3))+3H_(2)O to underset((R))(H_(3)BO_(3))+3HCl`
(iii) `BN+3H_(2)O to underset((R))(H_(3)BO_(3))+3HCl`
(iv) `underset((Q))(4BC l_(3))+3LiAlH_(4) to underset((S))(2B_(2)H_(6))+3LiCl+3AlCl_(3)`
(v ) `underset((S))(B_2H_(6)+6H_(2) O )to underset((R))(2H_(3)BO_(3))+6H_(3) uarr`
(vi ) ` underset((S))(B_(2) H_(6))+2NaH ) to underset((T))(2NaBH_(4))`
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(i) P+C("carbon")+Cl_(2) to Q+CO uaarr (ii) Q+H_(2)O to R+HCl (iii) BN+H_(2)O to R+NH_(3) uarr (iv) Q+LiAlH_(4) to S+LiCl+AlCl_(3) (v) S+H_(2) to R+H_(2) uarr (vi) S+NaH to T (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound T is used as a/an:

(i) P+C("carbon")+Cl_(2) to Q+CO uaarr (ii) Q+H_(2)O to R+HCl (iii) BN+H_(2)O to R+NH_(3) uarr (iv) Q+LiAlH_(4) to S+LiCl+AlCl_(3) (v) S+H_(2) to R+H_(2) uarr (vi) S+NaH to T (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound Q has: (I) zero dipole moment. (II) a planar trigonal structure (III) an electron deficient compound (IV) a lewis base Chose the correct code:

NaH(s)+H_(2)O to NaOH+H_(2)uarr

Na(s)+H_(2)O(l) overset(R.T.) to NaOH +H_(2) uarr

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