Concentrated `H_(2)SO_(4)` cannot be used to prepare HBr from NaBr , because it ,

Options

A. If both (A) and (R) are true and (R) is the correct explanation of (A)
B. if both (A) and (R) are true but (R) is not correct explanation of (A)
C. If (A) is true but (R) is false
D. If (A) is false but (R) is false

Answer

C

Explanation

First, HBr is released, being reducing in character, it is oxidised into `Br_(2)` by conc. `H_(2)SO_(4)`
`NaBr+H_(2)SO_(4) to NaHSO_(4)+HBr`
`2HBr+H_(2)SO_(4) to Br_(2)uarr+SO_(2)uarr+2H_(2)O`