The general formula of polythionate ion is `S_(n+2)O_(6)^(2-)`. If average oxidation state of 'S' atom is any polythionate ion is equal to bond order of 'S-O' bond. Then calculate the value of 'n' for the corresponding polythionate ion.

Answer

4

Explanation

bond orer of 'S-O' bond is 1.66 (5/3) average oxidation state of 'S' atom is:
`(10)/(2+n)=(5)/(3)`
(or) `(10)/(2+n)=(10)/(6) implies 2+n=6 impliesn=4`