Consider the following covalent compounds in their solid state and find the value of expression `(X+Y+Z)`.
`N_(2)O_(5),Cl_(2)O_(6),PC l_(),I_(2)Cl_(6),XeF_(6),PB r_(5)`
Where X=total number of compounds in which central atom of cationic or anionic part is `sp^(3)` hybridized.
Y=Total number of compounds having `90^(@)` bond angle either in cationic or anionic part.
Z=Total number of compounds having `109^(@)28'` bond angle either in cationic or anionic part.

Answer

9

Explanation

x=1+1+1+1=4
y=1+1=2
z=1+1+1=3
x+y+z=4+2+3=9