A sulphate of a metal (A) on heating evolves two gases (B) and ( C) and an oxide (D). Gas (B) turns `K_(2)Cr_(2)O_(7)` paper green while gas ( C) forms a trimer in which there is no `S-S` bond. Compound (D) with HCl, forms a Lewis acid (E ) which exists as a dimer. Compounds (A), (B), ( C),(D) and (E) are respectively:

Options

A. `FeSO_(4),SO_(2),SO_(3),Fe_(2)O_(3),FeCl_(3)`
B. `Al_(2)(SO_(4))_(3),SO_(2),SO_(3),Al_(2)O_(3),FeCl_(3)`
C. `FeS,SO_(2),SO_(3),FeSO_(4),FeCl_(3)`
D. `FeS,SO_(2),SO_(3),Fe_(2)(PO_(4))_(3),FeCl_(2)`

Answer

A

Explanation

`underset((A))(2FeSO_(4)) to underset((D))(Fe_(2)O_(3))+underset((B))(SO_(2))+underset((C))(SO_(3))`
`Fe_(2)O_(3)+6HCl to 2FeCl_(3)+3H_(2)O`