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A chemist opened a cupboard to find four...

A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1,2,3 contained colourless solutions, Whilst bottle 4 contained a blue solution. The labels from the bottles were lying scattered ont he floor of the cupboard.
They were
copper (II) sulphate
sodium carbonate
lead nitrate
hydrochloric acid
By mixing sammples of teh contents of the bottles, in pairs, the chemist made the following observations:
(i) Bottle 1 + Bottle 2 white precipitate
(ii) Bottle 1 + bottle 3 white precipitate
(iii) Bottle 1 + Bottle 4 white precipitate
(iv) Bottle 2 +Bottle 3 colourless gas evolved
(v) Bottle 2+ Bottle 4 no visible reaction
(vi) bottle 3 +bottle 4 blue precipitate
Q. Chemical formula of white precipitate in observation (i) is:

A

`CuCl_(2)`

B

`PbCl_(2)`

C

`PbCO_(3)`

D

`CuSO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

`Pb(NO_(3))_(2)+2HCl to underset("white")(PbCl_(2))darr+2HNO_(3)`
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