[" 1.Let "sum_(k=1)^(n)f(a+k)=16(2^(10)-1)," where the "],[" function "f" satisfics "f(x+y)=f(x)f(y)" for all "],[" natural numbers "x,y" and "f(1)=2" .Then the "],[" natural number " "a'" is "]

Let sum_(k=1)^(10)f(a+k)=16(2^(10)-1), where the function f satisfies f(x+y)=f(x)f(y) for all natural numbers x, y and f(1) = 2. Then, the natural number 'a' is

Let sum_(k=1)^(10)f(a+k)=16(2^(10)-1), where the function f satisfies f(x+y)=f(x)f(y) for all natural numbers x, y and f(1) = 2. Then, the natural number 'a' is

Find the natural no. a for which sum _(k=1)^nf(a+k)=16(2^n-1) where the function f satisfies f(x+y)=f(x)f(y) for all natural no. x,y, and further f(1)=2.

The natural number a for which sum_(k=1)^(n)f(a+k)=16(2^(n)-1) where the function f satisfies the relation f(x+y)=f(x)*f(y) for all natural numbers x,y and further f(1)=2 is

Find the natural number a for which sum_(k=1) ^(n)f(a+k)= 16(2^(n)-1) where the function f satisfies the relation f(x+y)=f(x)f(y) for all natural numbers x,y and further f(1)=2 .

Find the natural number a for which sum_(k=1)^(n)f(a+k)=16(2^(n)-1), where the function f satisfies the relation f(x+y)=f(x)f(y) for all natural number x,y and,further,f(1)=2.

Find the natural number a for which sum_(k=1)^(n)f(a+k)=16(2^(n)-1) where the function f satisfies the relation f(x+y)=f(x).f(y) for all natural numbers and also f(1)=2

Find the natural number a for which sum_(k=1)^nf(a+k)=16(2^n-1) where the function f satisifies f(x+y)=f(x)f(y) for x, y in N and f(1)=2.

The value of natural number 'a' for which sum_(k=1)^(n)f(a+k)=16(2^(n)-1) , where the function satisfies the relation f(x+y)=f(x).f(y) for all natural numbers x, y and further f(1)=2 is

The natural number a for which sum_(k=1,n) f(a+k)=16(2^n-1) where the function f satisfies the relation f(x+y)=f(x).f(y) for all natural numbers x,y and further f(1)=2 is:- A) 2 B) 3 C) 1 D) none of these