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If ` vec a` and ` vec b` are two vectors such that `| vec a|=4,| vec b|=3` and ` vec adot vec b=6` . Find the angle between ` vec a` and ` vec b` .

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Verified by Experts

We know, `veca*vecb = |veca|*|vecb|cos theta`
Putting given values,
`6 = 4*3*costheta`
`=>cos theta = 1/2`
`=>theta = 60^@`
So, the angle between `veca` and `vecb` is `60^@`.
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