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The amplitude and time period in SHM are...

The amplitude and time period in SHM are 0.8 cm and 0.2 sec respectively. If the initial phase is `pi//2` radian, then the equation representing SHM is -

A

`y=0.8cos 10pit`

B

`y=0.8sinpit`

C

`y=3xx0.8sinpit`

D

`y=0.8sin 10pit`

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The correct Answer is:
To find the equation representing the Simple Harmonic Motion (SHM) given the amplitude, time period, and initial phase, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - Amplitude \( A = 0.8 \) cm - Time period \( T = 0.2 \) sec - Initial phase \( \phi = \frac{\pi}{2} \) radians 2. **Convert Amplitude to Meters (if necessary):** - Since the amplitude is given in cm, we can convert it to meters for standard SI units: \[ A = 0.8 \, \text{cm} = 0.008 \, \text{m} \] 3. **Calculate Angular Frequency \( \omega \):** - The angular frequency \( \omega \) is related to the time period \( T \) by the formula: \[ \omega = \frac{2\pi}{T} \] - Substituting the given time period: \[ \omega = \frac{2\pi}{0.2} = 10\pi \, \text{rad/sec} \] 4. **Write the General Equation of SHM:** - The general equation for SHM can be expressed as: \[ y(t) = A \sin(\omega t + \phi) \] - Substituting the values we have: \[ y(t) = 0.008 \sin(10\pi t + \frac{\pi}{2}) \] 5. **Simplify Using Trigonometric Identity:** - We can use the trigonometric identity \( \sin\left(x + \frac{\pi}{2}\right) = \cos(x) \): \[ y(t) = 0.008 \cos(10\pi t) \] 6. **Final Equation:** - Therefore, the equation representing the SHM is: \[ y(t) = 0.008 \cos(10\pi t) \] ### Conclusion: The equation that represents the SHM is \( y(t) = 0.008 \cos(10\pi t) \).
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