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In a normal spinel types structure, the ...

In a normal spinel types structure, the oxide ions are arranged in ccp whereas 1/8 tetrahedral holes are occupied by `Zn^(2+)` ions and `50%` of octahedral holes are occupied by `Fe^(3+)` ions. The formula of the compound is -

A

`Zn_(2)Fe_(2)O_(4)`

B

`ZnFe_(2)O_(3)`

C

`ZnFe_(2)O_(4)`

D

`ZnFe_(2)O_(2)`

Text Solution

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The correct Answer is:
C
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