" 22."x^(2)-y^(2)-2y-1

Find the equation of the pair of direct commonr tangents to the circies x^(2)+y^(2)+22x+4y-100=0 and x^(2)+y^(2)-22x+4y+100=0

If the circle x^(2)+y^(2)+4x+22y+c=0 bisects the circumference of the circle x^(2)+y^(2)-2x+8y-d=0 then c+d

If the circle x^(2)+y^(2)+4x+22y+c=0 bisects the circumference of the circle x^(2)+y^(2)-2x+8y-d=0, then (c+d) is equal to

The radical centre of the circles x^(2)+y^(2)=9 , x^(2)+y^(2)-2x-2y-5=0 , x^(2)+y^(2)+4x+6y-19=0 is A) (0,0) (B) (1,1) (C) (2,2) (D) (3,3)

The equation of the tangent to the curve x^(2)-2xy+y^(2)+2x+y-6=0 at (2,2) is

A circle is concentric with circle x^(2)+y^(2)-2x+4y-20=0. If perimeter of the semicircle is 36 then the equation of the circle is: [use pi=22/7]x^(2)+y^(2)-2x+4y-44=0(x-1)^(2)+(y+2)^(2)=(126/11)^(2)x^(2)+y^(2)+(y+2y-43=0x^(2)=y^(2)-2x+4y-49=0

If the circle x^(2)+y^(2)+4x+22y+a=0 bisects the circumference of circle x^(2)+y^(2)-2x+8y+b=0, then a-b equals to

Find the direct common tangents of the circles. x^(2) + y^(2) + 22x - 4y - 100 =0 and x^(2) + y^(2) - 22x + 4y + 100 = 0.