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[12*(x)/(3)+1=(7)/(15)],[" Qolve "-1]...

[12*(x)/(3)+1=(7)/(15)],[" Qolve "-1]

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(2x)/(3)+1=(7x)/(15)+3

(2x)/3 + 1 = (7x)/15 + 3

Solve the equation *(x)/(3)+1=(7)/(15)

(1)4z+3=6+2z(2)(2x)/(3)+1=(7x)/(15)+3

15(x-1)+4(x+3)=2(7+x)

(12x + 17) / (3x + 1)-(2x + 15) / (x + 7) = 3 (1) / (5), x! =-(1) / (3), -7