[" (ii) "{cos(40^(@)+theta)-sin(50^(@)-8)" hesing "],[[" (a) "2cos theta," (b) "7sin theta," (c) "0]]

sin(50^(@)+theta)-cos(40^(@)-theta)

4cos^(3)40^(@)-3sin50^(@)=

The value of {cos(40^(@)+theta)-sin(50^(@)-theta)} is

cos (40^@ + theta) - sin (50^@ - theta) is equal to

The value of cos(40^@+theta)-sin(50^@-theta) is

Solve cos(50^(@)+ theta) = sin (30^(@)+theta) .

cos 40^(@)=0.76 then sin 50^(@) =………….

Value of [cos(40^@ + theta) - sin (50^@ - theta)] is

cos theta=8/10 , then find sin theta .

Prove that (i) " sin " (50^(@) + theta ) " cos " (20^(@) + theta) - " cos " (50^(@) + theta) " sin " (20^(@) + theta) =(1)/(2) (ii) " cos " (70^(@) + theta ) " cos " (10^(@) + theta ) + " sin " (70^(@) + theta) " sin " (10^(@) + theta)=(1)/(2)