[" 18.If "x=1+a+a^(2)+..." cond "y=1+b+b...

[" 18.If "x=1+a+a^(2)+..." cond "y=1+b+b^(2)+...oo" where "a" and "],[b" are proper fractions,then "1+ab+a^(2)b^(2)+..." co equals "],[[" (a) "(xy)/(y+x-1)," (b) "(x+y)/(x-y)],[" (c) "(x^(2)+y^(2))/(x-y)," (d) none of these "]]

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