The side AB of an isosceles triangle is along the axis of X with vertices A (-1,0) and AB =AC. The equation of the side BC when `angleA = 120^@` and `BC=4sqrt(3)` is :

The side AB of an isosceles triangle is along the axis of X with vertices A(-1,0) and AB=AC. The equation of the side BC when /_A=120^(@) and BC=4sqrt(3) is :

In an isosceles triangle ABC , angleA =120^@ ,a:b=

The extremities of the base of an isosceles triangle Delta ABC are the points A(2.0) and B(0,1). If the equation of the side AC is x=2 then the slope of the side BC

The equation of two equal sides AB and AC of an isosceies triangle ABC are x+y=5 and 7x-y=3 respectively Find the equations of the side BC if the area of the triangle ofABC is 5 units

The equations of two equal sides AB and AC of an isosceles triangle ABC are x + y = 5 and 7x - y = 3 respectively. What will be the equation of the side BC if area of triangle ABC is 5 square units.

The side BC of an equilateral triangle DABC is parallel to X-axis. Find the slopes of the lines along sides BC, CA and AB.

The side BC of an equilateral triangle DABC is parallel to X-axis. Find the slopes of the lines along sides BC, CA and AB.

The side BC of an equilateral triangle DABC is parallel to X-axis. Find the slopes of the lines along sides BC, CA and AB.